What is (3+i^{240}+2i)/(1-i^{415)-i}+i^{-17} ?

The solution to (3+i^{240}+2i)/(1-i^{415)-i}+i^{-17} is 4+i

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simplify (3+i^{240}+2i)/(1-i^{415)-i}+i^{-17}

simplify

\frac{3 + i ^{240} + 2 i}{1 - i ^{415} - i} + i^{- 17}

4 + i

Solution steps

\frac{3 + i ^{240} + 2 i}{1 - i ^{415} - i} + i^{- 17}

\frac{3 + i ^{240} + 2 i}{1 - i ^{415} - i} = \frac{4 + 2 i}{1}

i^{- 17} = \frac{- i}{1}

= \frac{4 + 2 i}{1} + \frac{- i}{1}

\frac{4 + 2 i}{1} = 4 + 2 i

\frac{- i}{1} = - i

= 4 + 2 i - i

Add similar elements:

2 i - i = i

= 4 + i

\frac{28 u ^{- 2} v ^{3}}{4 u ^{2} v ^{2}}

42 - 22

\frac{12 - 3 i}{3}

\frac{14 x ^{3} y ^{7}}{21 x ^{6} y ^{6}}

lo g_{4} (lo g_{3} (9))

What is (3+i^{240}+2i)/(1-i^{415)-i}+i^{-17} ?
The solution to (3+i^{240}+2i)/(1-i^{415)-i}+i^{-17} is 4+i