What are the solutions to the equation 4k^2+4k=5 ?

The solutions to the equation 4k^2+4k=5 are k=(-1+sqrt(6))/2 ,k=-(1+sqrt(6))/2

Find the zeros of 4k^2+4k=5

The zeros of 4k^2+4k=5 are k=(-1+sqrt(6))/2 ,k=-(1+sqrt(6))/2

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4 k^{2} + 4 k = 5

k = \frac{- 1 + 6}{2}, k = - \frac{1 + 6}{2}

Decimal Notation

k = 0.72474 \dots, k = - 1.72474 \dots

Solution steps

4 k^{2} + 4 k = 5

Move

5

to the left side

4 k^{2} + 4 k - 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 5) = 46

k_{1, 2} = \frac{- 4 \pm 4 6}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 4 + 4 6}{2 \cdot 4}, k_{2} = \frac{- 4 - 4 6}{2 \cdot 4}

k = \frac{- 4 + 4 6}{2 \cdot 4} : \frac{- 1 + 6}{2}

k = \frac{- 4 - 4 6}{2 \cdot 4} : - \frac{1 + 6}{2}

The solutions to the quadratic equation are:

k = \frac{- 1 + 6}{2}, k = - \frac{1 + 6}{2}

(2 - 4 d) (2 + 4 d) = 0

- 5 x - 4 > 21

6 \times 3

r^{2} + r - 90

- \frac{18}{4}

What are the solutions to the equation 4k^2+4k=5 ?
The solutions to the equation 4k^2+4k=5 are k=(-1+sqrt(6))/2 ,k=-(1+sqrt(6))/2
Find the zeros of 4k^2+4k=5
The zeros of 4k^2+4k=5 are k=(-1+sqrt(6))/2 ,k=-(1+sqrt(6))/2