What are the solutions to the equation x=2x^2+16x-14 ?

The solutions to the equation x=2x^2+16x-14 are x=(-15+sqrt(337))/4 ,x=(-15-sqrt(337))/4

Find the zeros of x=2x^2+16x-14

The zeros of x=2x^2+16x-14 are x=(-15+sqrt(337))/4 ,x=(-15-sqrt(337))/4

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x = 2 x^{2} + 16 x - 14

x = \frac{- 15 + 337}{4}, x = \frac{- 15 - 337}{4}

Decimal Notation

x = 0.83938 \dots, x = - 8.33938 \dots

Solution steps

x = 2 x^{2} + 16 x - 14

Switch sides

2 x^{2} + 16 x - 14 = x

Move

x

to the left side

2 x^{2} + 15 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 (- 14) = 337

x_{1, 2} = \frac{- 15 \pm 337}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 15 + 337}{2 \cdot 2}, x_{2} = \frac{- 15 - 337}{2 \cdot 2}

x = \frac{- 15 + 337}{2 \cdot 2} : \frac{- 15 + 337}{4}

x = \frac{- 15 - 337}{2 \cdot 2} : \frac{- 15 - 337}{4}

The solutions to the quadratic equation are:

x = \frac{- 15 + 337}{4}, x = \frac{- 15 - 337}{4}

j^{2} - 20 j + 100 = 0

(3 x + 1) (2 x - 1) - 2 x^{2} = (2 x - 3)^{2} + 6 x + 5

- \frac{7}{9} (x + 3) = 14

16 + 30 i

2 (3 y - 9) \geq 7 (2 y + 5)

What are the solutions to the equation x=2x^2+16x-14 ?
The solutions to the equation x=2x^2+16x-14 are x=(-15+sqrt(337))/4 ,x=(-15-sqrt(337))/4
Find the zeros of x=2x^2+16x-14
The zeros of x=2x^2+16x-14 are x=(-15+sqrt(337))/4 ,x=(-15-sqrt(337))/4