What are the solutions to the equation 4x^2-40x+100=0 ?

The solutions to the equation 4x^2-40x+100=0 are x=5

Find the zeros of 4x^2-40x+100=0

The zeros of 4x^2-40x+100=0 are x=5

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4 x^{2} - 40 x + 100 = 0

x = 5

Solution steps

4 x^{2} - 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 4 \cdot 100}{2 \cdot 4}

(- 40)^{2} - 4 \cdot 4 \cdot 100 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 40 )}{2 \cdot 4}

\frac{- ( - 40 )}{2 \cdot 4} = 5

x = 5

The solution to the quadratic equation is:

x = 5

\frac{1}{2} x^{2} + 5 x + \frac{1}{2} x^{2} = - 6

a, y = a e^{\frac{1}{2} (- 2)} + b e^{- \frac{1}{2} (- 2)}

\frac{( 4 - x )}{( - 2 )} \leq 1

m (b - a) - p (a - b)

49 t^{6} - 4 k^{8}

What are the solutions to the equation 4x^2-40x+100=0 ?
The solutions to the equation 4x^2-40x+100=0 are x=5
Find the zeros of 4x^2-40x+100=0
The zeros of 4x^2-40x+100=0 are x=5