What are the solutions to the equation 3x^2-6x-4=0 ?

The solutions to the equation 3x^2-6x-4=0 are x=(3+sqrt(21))/3 ,x=(3-sqrt(21))/3

Find the zeros of 3x^2-6x-4=0

The zeros of 3x^2-6x-4=0 are x=(3+sqrt(21))/3 ,x=(3-sqrt(21))/3

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3 x^{2} - 6 x - 4 = 0

x = \frac{3 + 21}{3}, x = \frac{3 - 21}{3}

Decimal Notation

x = 2.52752 \dots, x = - 0.52752 \dots

Solution steps

3 x^{2} - 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 4) = 221

x_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 21}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 21}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 21}{2 \cdot 3} : \frac{3 + 21}{3}

x = \frac{- ( - 6 ) - 2 21}{2 \cdot 3} : \frac{3 - 21}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 21}{3}, x = \frac{3 - 21}{3}

x^{5} - 7 x^{4} + 9 x^{3} + 23 x^{2} - 50 x + 24

\frac{2 π}{3.6}

1690 \cdot ⎩ ⎨ ⎧ \frac{[ ( 1 + 0.07 ) ^{38} - 1 ]}{0.07} ⎭ ⎬ ⎫

(x + 1) (x + 2) = 0

\frac{x + 5}{5} - \frac{x + 5}{24} = \frac{x + 6}{10} + \frac{x + 4}{60}

What are the solutions to the equation 3x^2-6x-4=0 ?
The solutions to the equation 3x^2-6x-4=0 are x=(3+sqrt(21))/3 ,x=(3-sqrt(21))/3
Find the zeros of 3x^2-6x-4=0
The zeros of 3x^2-6x-4=0 are x=(3+sqrt(21))/3 ,x=(3-sqrt(21))/3