What are the solutions to the equation 0=4x^2-64x+192 ?

The solutions to the equation 0=4x^2-64x+192 are x=12,x=4

Find the zeros of 0=4x^2-64x+192

The zeros of 0=4x^2-64x+192 are x=12,x=4

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0 = 4 x^{2} - 64 x + 192

x = 12, x = 4

Solution steps

0 = 4 x^{2} - 64 x + 192

Switch sides

4 x^{2} - 64 x + 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 64 ) \pm ( - 64 ) ^{2} - 4 \cdot 4 \cdot 192}{2 \cdot 4}

(- 64)^{2} - 4 \cdot 4 \cdot 192 = 32

x_{1, 2} = \frac{- ( - 64 ) \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 64 ) + 32}{2 \cdot 4}, x_{2} = \frac{- ( - 64 ) - 32}{2 \cdot 4}

x = \frac{- ( - 64 ) + 32}{2 \cdot 4} : 12

x = \frac{- ( - 64 ) - 32}{2 \cdot 4} : 4

The solutions to the quadratic equation are:

x = 12, x = 4

\frac{3}{∣ 2 x - 1 ∣} > 0

\frac{3}{4} (- 1) - \frac{( - 1 ) ^{2}}{2}

- 10 b + 5 = 7 b + 5

4 \cdot 16

x + \frac{x}{2} - 4 = \frac{x}{4}

What are the solutions to the equation 0=4x^2-64x+192 ?
The solutions to the equation 0=4x^2-64x+192 are x=12,x=4
Find the zeros of 0=4x^2-64x+192
The zeros of 0=4x^2-64x+192 are x=12,x=4