What are the solutions to the equation x^2-12x+19=6-10x ?

The solutions to the equation x^2-12x+19=6-10x are x=1+2sqrt(3)i,x=1-2sqrt(3)i

Find the zeros of x^2-12x+19=6-10x

The zeros of x^2-12x+19=6-10x are x=1+2sqrt(3)i,x=1-2sqrt(3)i

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x^{2} - 12 x + 19 = 6 - 10 x

x = 1 + 23 i, x = 1 - 23 i

Solution steps

x^{2} - 12 x + 19 = 6 - 10 x

Move

10 x

to the left side

x^{2} - 2 x + 19 = 6

Move

6

to the left side

x^{2} - 2 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 13 : 43 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 3 i}{2 \cdot 1} : 1 + 23 i

x = \frac{- ( - 2 ) - 4 3 i}{2 \cdot 1} : 1 - 23 i

The solutions to the quadratic equation are:

x = 1 + 23 i, x = 1 - 23 i

5 u^{2} + 24 u - 5

e^{\frac{2 πi}{4}}

36 x^{2} - 12 x + 1 = 4

t^{2} + 8 t

x^{2} + 5 x - 20 = 0

What are the solutions to the equation x^2-12x+19=6-10x ?
The solutions to the equation x^2-12x+19=6-10x are x=1+2sqrt(3)i,x=1-2sqrt(3)i
Find the zeros of x^2-12x+19=6-10x
The zeros of x^2-12x+19=6-10x are x=1+2sqrt(3)i,x=1-2sqrt(3)i