What are the solutions to the equation x^2+5x-20=0 ?

The solutions to the equation x^2+5x-20=0 are x=(-5+sqrt(105))/2 ,x=(-5-sqrt(105))/2

Find the zeros of x^2+5x-20=0

The zeros of x^2+5x-20=0 are x=(-5+sqrt(105))/2 ,x=(-5-sqrt(105))/2

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x^{2} + 5 x - 20 = 0

x = \frac{- 5 + 105}{2}, x = \frac{- 5 - 105}{2}

Decimal Notation

x = 2.62347 \dots, x = - 7.62347 \dots

Solution steps

x^{2} + 5 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 20) = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 105}{2 \cdot 1}, x_{2} = \frac{- 5 - 105}{2 \cdot 1}

x = \frac{- 5 + 105}{2 \cdot 1} : \frac{- 5 + 105}{2}

x = \frac{- 5 - 105}{2 \cdot 1} : \frac{- 5 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 105}{2}, x = \frac{- 5 - 105}{2}

1^{2} + b^{2} = 2^{2}

x - 3 = 2 + x

3 x^{2} - 16 x + 6 = 0

\frac{1}{2} - \frac{1}{8}

\frac{1}{x - 1} + \frac{2}{x} < 0

What are the solutions to the equation x^2+5x-20=0 ?
The solutions to the equation x^2+5x-20=0 are x=(-5+sqrt(105))/2 ,x=(-5-sqrt(105))/2
Find the zeros of x^2+5x-20=0
The zeros of x^2+5x-20=0 are x=(-5+sqrt(105))/2 ,x=(-5-sqrt(105))/2