What is (x+9)/((x-5)^2(x-8))<= 0 ?

The solution to (x+9)/((x-5)^2(x-8))<= 0 is -9<= x<5\lor 5<x<8

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(x+9)/((x-5)^2(x-8))<= 0

\frac{x + 9}{( x - 5 ) ^{2} ( x - 8 )} \leq 0

- 9 \leq x < 5 or 5 < x < 8

Interval Notation

[- 9, 5) \cup (5, 8)

Solution steps

\frac{x + 9}{( x - 5 ) ^{2} ( x - 8 )} \leq 0

Identify the intervals

- 9 \leq x < 5 or 5 < x < 8

2 - 2 x - 15 = 0

7 (3 - x) \geq 5

(16 x^{2} y^{4}) (\frac{1}{4} x^{5} y)

x = 4000 (1 + 0.7)^{2}

\frac{16 x ^{2} y}{24 x y ^{3}}

What is (x+9)/((x-5)^2(x-8))<= 0 ?
The solution to (x+9)/((x-5)^2(x-8))<= 0 is -9<= x<5\lor 5<x<8