What are the solutions to the equation 3t^2-6t-11=0 ?

The solutions to the equation 3t^2-6t-11=0 are t=(3+sqrt(42))/3 ,t=(3-sqrt(42))/3

Find the zeros of 3t^2-6t-11=0

The zeros of 3t^2-6t-11=0 are t=(3+sqrt(42))/3 ,t=(3-sqrt(42))/3

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3 t^{2} - 6 t - 11 = 0

t = \frac{3 + 42}{3}, t = \frac{3 - 42}{3}

Decimal Notation

t = 3.16024 \dots, t = - 1.16024 \dots

Solution steps

3 t^{2} - 6 t - 11 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 11) = 242

t_{1, 2} = \frac{- ( - 6 ) \pm 2 42}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 42}{2 \cdot 3}, t_{2} = \frac{- ( - 6 ) - 2 42}{2 \cdot 3}

t = \frac{- ( - 6 ) + 2 42}{2 \cdot 3} : \frac{3 + 42}{3}

t = \frac{- ( - 6 ) - 2 42}{2 \cdot 3} : \frac{3 - 42}{3}

The solutions to the quadratic equation are:

t = \frac{3 + 42}{3}, t = \frac{3 - 42}{3}

0 = (x - 8)^{2}

∣ x - 3 ∣ \leq 2 x - 5

5 u^{4} - 40 u^{3} + 35 u^{2}

2 x^{3} + 3 x^{2} - 8 x - 12

\frac{x - 2}{x ^{2} - 36} \geq 0

What are the solutions to the equation 3t^2-6t-11=0 ?
The solutions to the equation 3t^2-6t-11=0 are t=(3+sqrt(42))/3 ,t=(3-sqrt(42))/3
Find the zeros of 3t^2-6t-11=0
The zeros of 3t^2-6t-11=0 are t=(3+sqrt(42))/3 ,t=(3-sqrt(42))/3