What is 4x^{-3}\times 2x^2 ?

The solution to 4x^{-3}\times 2x^2 is 8/x

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simplify 4x^{-3}\times 2x^2

simplify

4 x^{- 3} \cdot 2 x^{2}

\frac{8}{x}

Solution steps

4 x^{- 3} \cdot 2 x^{2}

Multiply the numbers:

4 \cdot 2 = 8

= 8 x^{- 3} x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{- 3} x^{2} = x^{- 3 + 2}

= 8 x^{- 3 + 2}

Add/Subtract the numbers:

- 3 + 2 = - 1

= 8 x^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{- 1} = \frac{1}{x}

= 8 \cdot \frac{1}{x}

Simplify

8 \cdot \frac{1}{x} : \frac{8}{x}

= \frac{8}{x}

\frac{x ^{2} - 4}{x ^{2} - 5 x + 6}

x (x^{2} - x + 3)

b^{2} - 4 b + 3

\frac{3}{4} - \frac{1}{2}