What are the solutions to the equation (3x-4)(4x-3)-(2x-7)(3x-2)=214 ?

The solutions to the equation (3x-4)(4x-3)-(2x-7)(3x-2)=214 are x=6,x=-6

Find the zeros of (3x-4)(4x-3)-(2x-7)(3x-2)=214

The zeros of (3x-4)(4x-3)-(2x-7)(3x-2)=214 are x=6,x=-6

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(3 x - 4) (4 x - 3) - (2 x - 7) (3 x - 2) = 214

x = 6, x = - 6

Solution steps

(3 x - 4) (4 x - 3) - (2 x - 7) (3 x - 2) = 214

Expand

(3 x - 4) (4 x - 3) - (2 x - 7) (3 x - 2) : 6 x^{2} - 2

6 x^{2} - 2 = 214

Move

214

to the left side

6 x^{2} - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 6 ( - 216 )}{2 \cdot 6}

0^{2} - 4 \cdot 6 (- 216) = 72

x_{1, 2} = \frac{- 0 \pm 72}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 0 + 72}{2 \cdot 6}, x_{2} = \frac{- 0 - 72}{2 \cdot 6}

x = \frac{- 0 + 72}{2 \cdot 6} : 6

x = \frac{- 0 - 72}{2 \cdot 6} : - 6

The solutions to the quadratic equation are:

x = 6, x = - 6

\frac{5}{3} \cdot 5

x \cdot (x + 4) = x^{2} + 8

m^{2} - m - 88 = 0

3 ∣ 3 x ∣ + 4 = 16

\frac{49 x ^{2} - 81}{x ^{2} - 64} \leq 0

What are the solutions to the equation (3x-4)(4x-3)-(2x-7)(3x-2)=214 ?
The solutions to the equation (3x-4)(4x-3)-(2x-7)(3x-2)=214 are x=6,x=-6
Find the zeros of (3x-4)(4x-3)-(2x-7)(3x-2)=214
The zeros of (3x-4)(4x-3)-(2x-7)(3x-2)=214 are x=6,x=-6