What is factor 4x^4+9x^3-5x^2+9x-9 ?

The solution to factor 4x^4+9x^3-5x^2+9x-9 is (x+3)(4x-3)(x^2+1)

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factor 4x^4+9x^3-5x^2+9x-9

factor

4 x^{4} + 9 x^{3} - 5 x^{2} + 9 x - 9

(x + 3) (4 x - 3) (x^{2} + 1)

Solution steps

4 x^{4} + 9 x^{3} - 5 x^{2} + 9 x - 9

Use the rational root theorem

= (x + 3) \frac{4 x ^{4} + 9 x ^{3} - 5 x ^{2} + 9 x - 9}{x + 3}

\frac{4 x ^{4} + 9 x ^{3} - 5 x ^{2} + 9 x - 9}{x + 3} = 4 x^{3} - 3 x^{2} + 4 x - 3

= (x + 3) (4 x^{3} - 3 x^{2} + 4 x - 3)

Factor

4 x^{3} - 3 x^{2} + 4 x - 3 : (4 x - 3) (x^{2} + 1)

= (x + 3) (4 x - 3) (x^{2} + 1)

\frac{2}{9} - \frac{1}{9}

\frac{10}{5} + \frac{9}{10}

\frac{4 x ^{3} + 16 x ^{2} - 29 x + 10}{2 x - 1}

+ 4 c^{2} - 1

- \frac{1}{4} + \frac{3}{5}

What is factor 4x^4+9x^3-5x^2+9x-9 ?
The solution to factor 4x^4+9x^3-5x^2+9x-9 is (x+3)(4x-3)(x^2+1)