What are the solutions to the equation 2n(3n+3)=0 ?

The solutions to the equation 2n(3n+3)=0 are n=0,n=-1

Find the zeros of 2n(3n+3)=0

The zeros of 2n(3n+3)=0 are n=0,n=-1

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2 n (3 n + 3) = 0

n = 0, n = - 1

Solution steps

2 n (3 n + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n = 0 or 3 n + 3 = 0

Solve

3 n + 3 = 0 : n = - 1

The solutions to the quadratic equation are:

n = 0, n = - 1

\frac{x - 5}{x - 2} < 2

x^{2} - 4 x + 3 < 0

\frac{8}{( 2 + 1 ) ^{3}}

\frac{2}{3} \cdot \frac{2}{3} x = - \frac{6}{1} \cdot \frac{2}{3}

x^{4} y^{2} + x^{3} y^{3}

What are the solutions to the equation 2n(3n+3)=0 ?
The solutions to the equation 2n(3n+3)=0 are n=0,n=-1
Find the zeros of 2n(3n+3)=0
The zeros of 2n(3n+3)=0 are n=0,n=-1