What are the solutions to the equation x^2+13x+40=0 ?

The solutions to the equation x^2+13x+40=0 are x=-5,x=-8

Find the zeros of x^2+13x+40=0

The zeros of x^2+13x+40=0 are x=-5,x=-8

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x^{2} + 13 x + 40 = 0

x = - 5, x = - 8

Solution steps

x^{2} + 13 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 40 = 3

x_{1, 2} = \frac{- 13 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 3}{2 \cdot 1}, x_{2} = \frac{- 13 - 3}{2 \cdot 1}

x = \frac{- 13 + 3}{2 \cdot 1} : - 5

x = \frac{- 13 - 3}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 5, x = - 8

x^{3} - x^{2} - 12 x + 12

X^{2} + 4 X + 2 = 0

2 n^{2} + 6 n - 108

8 w^{3} - 125

(8^{\frac{3}{4}} + 2^{3})^{\frac{1}{2}}

What are the solutions to the equation x^2+13x+40=0 ?
The solutions to the equation x^2+13x+40=0 are x=-5,x=-8
Find the zeros of x^2+13x+40=0
The zeros of x^2+13x+40=0 are x=-5,x=-8