What are the solutions to the equation 15b^2+4b-4=0 ?

The solutions to the equation 15b^2+4b-4=0 are b= 2/5 ,b=-2/3

Find the zeros of 15b^2+4b-4=0

The zeros of 15b^2+4b-4=0 are b= 2/5 ,b=-2/3

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15 b^{2} + 4 b - 4 = 0

b = \frac{2}{5}, b = - \frac{2}{3}

Solution steps

15 b^{2} + 4 b - 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 15 ( - 4 )}{2 \cdot 15}

4^{2} - 4 \cdot 15 (- 4) = 16

b_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 15}

Separate the solutions

b_{1} = \frac{- 4 + 16}{2 \cdot 15}, b_{2} = \frac{- 4 - 16}{2 \cdot 15}

b = \frac{- 4 + 16}{2 \cdot 15} : \frac{2}{5}

b = \frac{- 4 - 16}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

b = \frac{2}{5}, b = - \frac{2}{3}

∣ x ∣ - 1 = 2 x + 2

0 \leq - 2 x^{2} + 8 x + 8 \leq 10

(3 - 2 i) (4 + i)

(x - 4) (x + 2) = 16

(x + 1)^{2} (x - 3) (x - 8) < 0

What are the solutions to the equation 15b^2+4b-4=0 ?
The solutions to the equation 15b^2+4b-4=0 are b= 2/5 ,b=-2/3
Find the zeros of 15b^2+4b-4=0
The zeros of 15b^2+4b-4=0 are b= 2/5 ,b=-2/3