What are the solutions to the equation 6^2+15^2=c^2 ?

The solutions to the equation 6^2+15^2=c^2 are c=3sqrt(29),c=-3sqrt(29)

Find the zeros of 6^2+15^2=c^2

The zeros of 6^2+15^2=c^2 are c=3sqrt(29),c=-3sqrt(29)

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6^{2} + 1 5^{2} = c^{2}

c = 329, c = - 329

Decimal Notation

c = 16.15549 \dots, c = - 16.15549 \dots

Solution steps

6^{2} + 1 5^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 1 5^{2}

Simplify

6^{2} + 1 5^{2} : 261

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 261, c = - 261

261 = 329

- 261 = - 329

c = 329, c = - 329

10 x + 2 (x - 6) = 3 (4 x - 4)

\frac{2}{3} - \frac{7}{2} \cdot \frac{1}{13}

2 (7 x + 4) = 4 x - 6 (2 - x) + 7

x^{2} + 33 = 14 x

∣ x - 2 ∣ \leq 7

What are the solutions to the equation 6^2+15^2=c^2 ?
The solutions to the equation 6^2+15^2=c^2 are c=3sqrt(29),c=-3sqrt(29)
Find the zeros of 6^2+15^2=c^2
The zeros of 6^2+15^2=c^2 are c=3sqrt(29),c=-3sqrt(29)