What is |x-3|-|x+1|>2 ?

The solution to |x-3|-|x+1|>2 is x<0

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|x-3|-|x+1|>2

∣ x - 3 ∣ - ∣ x + 1 ∣ > 2

x < 0

Interval Notation

(- \infty, 0)

Solution steps

∣ x - 3 ∣ - ∣ x + 1 ∣ > 2

Find positive and negative intervals

x < - 1, - 1 \leq x < 3, x \geq 3

Solve the inequality for each interval

x < - 1 or - 1 \leq x < 0 or No Solution

Merge Overlapping Intervals

x < 0

x \geq - 1 and x \leq 8

w^{2} - 10 w + 24 = 0

lo g_{5} (525) = L

\frac{3 π}{8} - \frac{π}{2}

(\frac{18}{2})^{2}