What is factor j^2-24j+23 ?

The solution to factor j^2-24j+23 is (j-1)(j-23)

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factor j^2-24j+23

factor

j^{2} - 24 j + 23

(j - 1) (j - 23)

Solution steps

j^{2} - 24 j + 23

Break the expression into groups

= (j^{2} - j) + (- 23 j + 23)

Factor out

j

from

j^{2} - j : j (j - 1)

Factor out

- 23

from

- 23 j + 23 : - 23 (j - 1)

= j (j - 1) - 23 (j - 1)

Factor out common term

j - 1

= (j - 1) (j - 23)

(a^{2} + 1)^{2} + 5 (a^{2} + 1) - 24

6 - 5 x \leq - 44

y^{2} - 6 y + 25 = 0

(8 a^{- 3})^{- \frac{2}{3}}

2 x^{4} + 23 x^{3} + 49 x^{2} + 23 x + 2