What are the solutions to the equation y^2-6y+25=0 ?

The solutions to the equation y^2-6y+25=0 are y=3+4i,y=3-4i

Find the zeros of y^2-6y+25=0

The zeros of y^2-6y+25=0 are y=3+4i,y=3-4i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 6 y + 25 = 0

y = 3 + 4 i, y = 3 - 4 i

Solution steps

y^{2} - 6 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

y_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

y = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

y = 3 + 4 i, y = 3 - 4 i

(8 a^{- 3})^{- \frac{2}{3}}

2 x^{4} + 23 x^{3} + 49 x^{2} + 23 x + 2

3^{- 1} + 2^{- 1}

x^{2} + 4 x = 77

\frac{x - y}{y ^{2} + x y - 2 x ^{2}}

What are the solutions to the equation y^2-6y+25=0 ?
The solutions to the equation y^2-6y+25=0 are y=3+4i,y=3-4i
Find the zeros of y^2-6y+25=0
The zeros of y^2-6y+25=0 are y=3+4i,y=3-4i