What is cube root of x-1}>\sqrt[3]{5-x ?

The solution to cube root of x-1}>\sqrt[3]{5-x is x>3

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cube root of x-1}>\sqrt[3]{5-x

x > 3

Interval Notation

(3, \infty)

Solution steps

Take both sides of the equation to the power of

3

Simplify

x - 1 > 5 - x

x - 1 > 5 - x : x > 3

x > 3

18 q - 2 q^{2} = 0

x^{2} - 32 = - 4 x

\frac{3}{8} x - \frac{1}{3} x + 6 = \frac{1}{6} x

(3 x^{2} y) (x y^{3})^{2}

6 x - 6 \leq 6 (x - 1)

What is cube root of x-1}>\sqrt[3]{5-x ?
The solution to cube root of x-1}>\sqrt[3]{5-x is x>3