What are the solutions to the equation x^2-25x=0 ?

The solutions to the equation x^2-25x=0 are x=25,x=0

Find the zeros of x^2-25x=0

The zeros of x^2-25x=0 are x=25,x=0

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x^{2} - 25 x = 0

x = 25, x = 0

Solution steps

x^{2} - 25 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 0 = 25

x_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 1}

x = \frac{- ( - 25 ) + 25}{2 \cdot 1} : 25

x = \frac{- ( - 25 ) - 25}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 25, x = 0

(4 x + 16)^{2} + x^{2} = (4 x + 17)^{2}

\frac{x}{10} = \frac{2}{8}

2^{- 4} = \frac{1}{16}

(4 k)^{2}

4 x^{2} - 6 x - 3 = 0

What are the solutions to the equation x^2-25x=0 ?
The solutions to the equation x^2-25x=0 are x=25,x=0
Find the zeros of x^2-25x=0
The zeros of x^2-25x=0 are x=25,x=0