What are the solutions to the equation -x^2+4x=10 ?

The solutions to the equation -x^2+4x=10 are x=2-sqrt(6)i,x=2+sqrt(6)i

Find the zeros of -x^2+4x=10

The zeros of -x^2+4x=10 are x=2-sqrt(6)i,x=2+sqrt(6)i

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- x^{2} + 4 x = 10

x = 2 - 6 i, x = 2 + 6 i

Solution steps

- x^{2} + 4 x = 10

Move

10

to the left side

- x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 10) : 26 i

x_{1, 2} = \frac{- 4 \pm 2 6 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 6 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 6 i}{2 ( - 1 )}

x = \frac{- 4 + 2 6 i}{2 ( - 1 )} : 2 - 6 i

x = \frac{- 4 - 2 6 i}{2 ( - 1 )} : 2 + 6 i

The solutions to the quadratic equation are:

x = 2 - 6 i, x = 2 + 6 i

5 x + 1 = 2 x - 5

\frac{3 x}{4} - 7 = - 9

x^{2} + 4 x - 5 < x - 1

(4 x + 3) (x + 1) = 1

12 x^{2} - 3

What are the solutions to the equation -x^2+4x=10 ?
The solutions to the equation -x^2+4x=10 are x=2-sqrt(6)i,x=2+sqrt(6)i
Find the zeros of -x^2+4x=10
The zeros of -x^2+4x=10 are x=2-sqrt(6)i,x=2+sqrt(6)i