What are the solutions to the equation (x+10)(2x-5)=0 ?

The solutions to the equation (x+10)(2x-5)=0 are x=-10,x= 5/2

Find the zeros of (x+10)(2x-5)=0

The zeros of (x+10)(2x-5)=0 are x=-10,x= 5/2

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(x + 10) (2 x - 5) = 0

x = - 10, x = \frac{5}{2}

Decimal Notation

x = - 10, x = 2.5

Solution steps

(x + 10) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 10 = 0 or 2 x - 5 = 0

Solve

x + 10 = 0 : x = - 10

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - 10, x = \frac{5}{2}

\frac{7 - 3 i}{2 i}

s^{2} - 2 s - 15 = 0

x^{5} \cdot x^{2}

2 \cdot \frac{5}{8}

8 x^{2} - 16 x + 6 = 0

What are the solutions to the equation (x+10)(2x-5)=0 ?
The solutions to the equation (x+10)(2x-5)=0 are x=-10,x= 5/2
Find the zeros of (x+10)(2x-5)=0
The zeros of (x+10)(2x-5)=0 are x=-10,x= 5/2