What is x+5-1/(x+3)\times (x^2-9) ?

The solution to x+5-1/(x+3)\times (x^2-9) is 8

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simplify x+5-1/(x+3)\times (x^2-9)

simplify

x + 5 - \frac{1}{x + 3} \cdot (x^{2} - 9)

8

Solution steps

x + 5 - \frac{1}{x + 3} (x^{2} - 9)

Simplify

\frac{1}{x + 3} (x^{2} - 9) : x - 3

= x + 5 - (x - 3)

Apply the distributive law:

- (a - b) = - a + b

- (x - 3) = - x + 3

= x + 5 - x + 3

Group like terms

= x - x + 5 + 3

Add similar elements:

x - x = 0

= 5 + 3

Add the numbers:

5 + 3 = 8

= 8

2 (8)

0 \times \frac{1}{3}

1 - \frac{3}{6}

\frac{- 4}{x - 4} + \frac{x ^{2} - 2 x}{2 x - 8}

\frac{1}{2} s + \frac{3}{4} s + \frac{1}{4} s + 4

What is x+5-1/(x+3)\times (x^2-9) ?
The solution to x+5-1/(x+3)\times (x^2-9) is 8