What are the solutions to the equation f^2-8f+12=0 ?

The solutions to the equation f^2-8f+12=0 are f=6,f=2

Find the zeros of f^2-8f+12=0

The zeros of f^2-8f+12=0 are f=6,f=2

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f^{2} - 8 f + 12 = 0

f = 6, f = 2

Solution steps

f^{2} - 8 f + 12 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

f_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

Separate the solutions

f_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, f_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

f = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

f = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

f = 6, f = 2

(z + 2)^{2} = - 13

\frac{4}{10} x - 2 x + \frac{8}{5} = \frac{4}{5}

14 x^{2} = - 21 x

11 + 15 x = - 7 + 13 x

8000 = 8 x - (6.06 x + 15000)

What are the solutions to the equation f^2-8f+12=0 ?
The solutions to the equation f^2-8f+12=0 are f=6,f=2
Find the zeros of f^2-8f+12=0
The zeros of f^2-8f+12=0 are f=6,f=2