What is x^2+2x+4-(3x-1) ?

The solution to x^2+2x+4-(3x-1) is x^2-x+5

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simplify x^2+2x+4-(3x-1)

simplify

x^{2} + 2 x + 4 - (3 x - 1)

x^{2} - x + 5

Solution steps

x^{2} + 2 x + 4 - (3 x - 1)

Apply the distributive law:

- (a - b) = - a + b

- (3 x - 1) = - 3 x + 1

= x^{2} + 2 x + 4 - 3 x + 1

Group like terms

= x^{2} + 2 x - 3 x + 4 + 1

Add similar elements:

2 x - 3 x = - x

= x^{2} - x + 4 + 1

Add the numbers:

4 + 1 = 5

= x^{2} - x + 5

n^{2} + 4 n - 32

\frac{6 + 32}{2}

- \frac{1}{( 0 + 1 ) ^{2}}

(2 - \frac{2}{3} x)^{2}

sin (3 t) cos (3 t)