What are the solutions to the equation s^2+s+2=0 ?

The solutions to the equation s^2+s+2=0 are s=-1/2+i(sqrt(7))/2 ,s=-1/2-i(sqrt(7))/2

Find the zeros of s^2+s+2=0

The zeros of s^2+s+2=0 are s=-1/2+i(sqrt(7))/2 ,s=-1/2-i(sqrt(7))/2

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s^{2} + s + 2 = 0

s = - \frac{1}{2} + i \frac{7}{2}, s = - \frac{1}{2} - i \frac{7}{2}

Solution steps

s^{2} + s + 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 2 : 7 i

s_{1, 2} = \frac{- 1 \pm 7 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 1 + 7 i}{2 \cdot 1}, s_{2} = \frac{- 1 - 7 i}{2 \cdot 1}

s = \frac{- 1 + 7 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{7}{2}

s = \frac{- 1 - 7 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

s = - \frac{1}{2} + i \frac{7}{2}, s = - \frac{1}{2} - i \frac{7}{2}

lo g_{10} (0.001)

(\frac{u ^{5}}{u ^{4} u ^{4}})^{- 5}

3 (3 - x) = 9 - 3 x

\frac{20 c d}{28 b c d}

8 = \frac{1}{3} (4) + b

What are the solutions to the equation s^2+s+2=0 ?
The solutions to the equation s^2+s+2=0 are s=-1/2+i(sqrt(7))/2 ,s=-1/2-i(sqrt(7))/2
Find the zeros of s^2+s+2=0
The zeros of s^2+s+2=0 are s=-1/2+i(sqrt(7))/2 ,s=-1/2-i(sqrt(7))/2