What is factor x^6+6x^4+9x^2+4 ?

The solution to factor x^6+6x^4+9x^2+4 is (x^2+1)^2(x^2+4)

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factor x^6+6x^4+9x^2+4

factor

x^{6} + 6 x^{4} + 9 x^{2} + 4

(x^{2} + 1)^{2} (x^{2} + 4)

Solution steps

x^{6} + 6 x^{4} + 9 x^{2} + 4

Let

u = x^{2}

= u^{3} + 6 u^{2} + 9 u + 4

Factor

u^{3} + 6 u^{2} + 9 u + 4 : (u + 1) (u + 1) (u + 4)

= (u + 1) (u + 1) (u + 4)

Substitute back

u = x^{2}

= (x^{2} + 1) (x^{2} + 1) (x^{2} + 4)

Apply exponent rule:

aa = a^{2}

(x^{2} + 1) (x^{2} + 1) = (x^{2} + 1)^{2}

= (x^{2} + 1)^{2} (x^{2} + 4)

r^{3} - 3 r^{2} + 3 r - 1

35 \cdot 55

(- x^{2} + 2 x)^{2}

(3 + 2 i) - (1 - 6 i)

+ 8 x y - 32 x z + 40 x

What is factor x^6+6x^4+9x^2+4 ?
The solution to factor x^6+6x^4+9x^2+4 is (x^2+1)^2(x^2+4)