What is (3x^2+19x+20)/(6x^2+17x+12) ?

The solution to (3x^2+19x+20)/(6x^2+17x+12) is (x+5)/(2x+3)

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simplify (3x^2+19x+20)/(6x^2+17x+12)

simplify

\frac{3 x ^{2} + 19 x + 20}{6 x ^{2} + 17 x + 12}

\frac{x + 5}{2 x + 3}

Solution steps

\frac{3 x ^{2} + 19 x + 20}{6 x ^{2} + 17 x + 12}

Factor

3 x^{2} + 19 x + 20 : (3 x + 4) (x + 5)

= \frac{( 3 x + 4 ) ( x + 5 )}{6 x ^{2} + 17 x + 12}

Factor

6 x^{2} + 17 x + 12 : (3 x + 4) (2 x + 3)

= \frac{( 3 x + 4 ) ( x + 5 )}{( 3 x + 4 ) ( 2 x + 3 )}

Cancel the common factor:

3 x + 4

= \frac{x + 5}{2 x + 3}

- 3 x^{2} + 36 x - 81

\frac{3 5 ^{- 4.7} \times 7 ^{5.7}}{5 ^{- 3.7}}

4 r^{4} + r^{2}

lo g_{10} (4) (32)

What is (3x^2+19x+20)/(6x^2+17x+12) ?
The solution to (3x^2+19x+20)/(6x^2+17x+12) is (x+5)/(2x+3)