What are the solutions to the equation -x^2-2x-25=0 ?

The solutions to the equation -x^2-2x-25=0 are x=-1-2sqrt(6)i,x=-1+2sqrt(6)i

Find the zeros of -x^2-2x-25=0

The zeros of -x^2-2x-25=0 are x=-1-2sqrt(6)i,x=-1+2sqrt(6)i

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- x^{2} - 2 x - 25 = 0

x = - 1 - 26 i, x = - 1 + 26 i

Solution steps

- x^{2} - 2 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

Simplify

(- 2)^{2} - 4 (- 1) (- 25) : 46 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 6 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 6 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4 6 i}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4 6 i}{2 ( - 1 )} : - 1 - 26 i

x = \frac{- ( - 2 ) - 4 6 i}{2 ( - 1 )} : - 1 + 26 i

The solutions to the quadratic equation are:

x = - 1 - 26 i, x = - 1 + 26 i

4 = x^{2} - 7

- 0.6 (2)^{2} + 4.8 (2)

6 x^{2} + 11 x - 35

\frac{2 x + 5}{6} - \frac{2 x}{3} = - \frac{1}{2}

\frac{x - 6}{7} + 8 = - 1

What are the solutions to the equation -x^2-2x-25=0 ?
The solutions to the equation -x^2-2x-25=0 are x=-1-2sqrt(6)i,x=-1+2sqrt(6)i
Find the zeros of -x^2-2x-25=0
The zeros of -x^2-2x-25=0 are x=-1-2sqrt(6)i,x=-1+2sqrt(6)i