What are the solutions to the equation x^2-18x+68=0 ?

The solutions to the equation x^2-18x+68=0 are x=9+sqrt(13),x=9-sqrt(13)

Find the zeros of x^2-18x+68=0

The zeros of x^2-18x+68=0 are x=9+sqrt(13),x=9-sqrt(13)

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x^{2} - 18 x + 68 = 0

x = 9 + 13, x = 9 - 13

Solution steps

x^{2} - 18 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 68}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 68 = 213

x_{1, 2} = \frac{- ( - 18 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 13}{2 \cdot 1} : 9 + 13

x = \frac{- ( - 18 ) - 2 13}{2 \cdot 1} : 9 - 13

The solutions to the quadratic equation are:

x = 9 + 13, x = 9 - 13

5 x - 7 = - 22

2 - \frac{4}{9}

7 x - x^{2} = 10

49 x^{2} - 64

3 z^{2} + 3 z - 6 = 0

What are the solutions to the equation x^2-18x+68=0 ?
The solutions to the equation x^2-18x+68=0 are x=9+sqrt(13),x=9-sqrt(13)
Find the zeros of x^2-18x+68=0
The zeros of x^2-18x+68=0 are x=9+sqrt(13),x=9-sqrt(13)