What are the solutions to the equation 3z^2+3z-6=0 ?

The solutions to the equation 3z^2+3z-6=0 are z=1,z=-2

Find the zeros of 3z^2+3z-6=0

The zeros of 3z^2+3z-6=0 are z=1,z=-2

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3 z^{2} + 3 z - 6 = 0

z = 1, z = - 2

Solution steps

3 z^{2} + 3 z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 6) = 9

z_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 3 + 9}{2 \cdot 3}, z_{2} = \frac{- 3 - 9}{2 \cdot 3}

z = \frac{- 3 + 9}{2 \cdot 3} : 1

z = \frac{- 3 - 9}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

z = 1, z = - 2

- 10 f + 1 > - f - 5

10 + \frac{h}{3} = 1

x^{2} + 25 = 6 x

1 - 4 k < 0

15 - 15 x = (4 x + 1) (x - 1)

What are the solutions to the equation 3z^2+3z-6=0 ?
The solutions to the equation 3z^2+3z-6=0 are z=1,z=-2
Find the zeros of 3z^2+3z-6=0
The zeros of 3z^2+3z-6=0 are z=1,z=-2