What is factor x^4-4x^3-5x^2+16x+4 ?

The solution to factor x^4-4x^3-5x^2+16x+4 is (x-2)(x+2)(x^2-4x-1)

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factor x^4-4x^3-5x^2+16x+4

factor

x^{4} - 4 x^{3} - 5 x^{2} + 16 x + 4

(x - 2) (x + 2) (x^{2} - 4 x - 1)

Solution steps

x^{4} - 4 x^{3} - 5 x^{2} + 16 x + 4

Use the rational root theorem

= (x - 2) \frac{x ^{4} - 4 x ^{3} - 5 x ^{2} + 16 x + 4}{x - 2}

\frac{x ^{4} - 4 x ^{3} - 5 x ^{2} + 16 x + 4}{x - 2} = x^{3} - 2 x^{2} - 9 x - 2

= (x - 2) (x^{3} - 2 x^{2} - 9 x - 2)

Factor

x^{3} - 2 x^{2} - 9 x - 2 : (x + 2) (x^{2} - 4 x - 1)

= (x - 2) (x + 2) (x^{2} - 4 x - 1)

(- 3 x + 6)^{2}

- 2 x^{2} - 3 x

\frac{y ^{4}}{8} + \frac{1}{4 y ^{2}}

lo g_{10} (9) (3)

lo g_{5} (5^{\frac{1}{3}})

What is factor x^4-4x^3-5x^2+16x+4 ?
The solution to factor x^4-4x^3-5x^2+16x+4 is (x-2)(x+2)(x^2-4x-1)