What are the solutions to the equation -24x^2-12x+120=0 ?

The solutions to the equation -24x^2-12x+120=0 are x=-5/2 ,x=2

Find the zeros of -24x^2-12x+120=0

The zeros of -24x^2-12x+120=0 are x=-5/2 ,x=2

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- 24 x^{2} - 12 x + 120 = 0

x = - \frac{5}{2}, x = 2

Decimal Notation

x = - 2.5, x = 2

Solution steps

- 24 x^{2} - 12 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 24 ) \cdot 120}{2 ( - 24 )}

(- 12)^{2} - 4 (- 24) \cdot 120 = 108

x_{1, 2} = \frac{- ( - 12 ) \pm 108}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 108}{2 ( - 24 )}, x_{2} = \frac{- ( - 12 ) - 108}{2 ( - 24 )}

x = \frac{- ( - 12 ) + 108}{2 ( - 24 )} : - \frac{5}{2}

x = \frac{- ( - 12 ) - 108}{2 ( - 24 )} : 2

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 2

5 x^{2} - 3 = 32

\frac{10 !}{3 ! 2 !}

2 x^{2} + 2 = - 4 x

x^{2} - 2 x < 15

- 3 x^{2} - 6 x = 0

What are the solutions to the equation -24x^2-12x+120=0 ?
The solutions to the equation -24x^2-12x+120=0 are x=-5/2 ,x=2
Find the zeros of -24x^2-12x+120=0
The zeros of -24x^2-12x+120=0 are x=-5/2 ,x=2