What are the solutions to the equation 3t^2-12=0 ?

The solutions to the equation 3t^2-12=0 are t=2,t=-2

Find the zeros of 3t^2-12=0

The zeros of 3t^2-12=0 are t=2,t=-2

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3 t^{2} - 12 = 0

t = 2, t = - 2

Solution steps

3 t^{2} - 12 = 0

Move

12

to the right side

3 t^{2} = 12

Divide both sides by

3

t^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 4, t = - 4

4 = 2

- 4 = - 2

t = 2, t = - 2

2 x - 5 x (2 - x) = 3 x - 7

23.8 = 3.5 b

s^{2} = 20

- 2 x^{2} + 7 x + 5 = 0

\frac{2 x - 5}{x - 2} - 1 > 0

What are the solutions to the equation 3t^2-12=0 ?
The solutions to the equation 3t^2-12=0 are t=2,t=-2
Find the zeros of 3t^2-12=0
The zeros of 3t^2-12=0 are t=2,t=-2