What is factor x^4+4x^3-x^2-16x-12 ?

The solution to factor x^4+4x^3-x^2-16x-12 is (x+1)(x+3)(x+2)(x-2)

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factor x^4+4x^3-x^2-16x-12

factor

x^{4} + 4 x^{3} - x^{2} - 16 x - 12

(x + 1) (x + 3) (x + 2) (x - 2)

Solution steps

x^{4} + 4 x^{3} - x^{2} - 16 x - 12

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 4 x ^{3} - x ^{2} - 16 x - 12}{x + 1}

\frac{x ^{4} + 4 x ^{3} - x ^{2} - 16 x - 12}{x + 1} = x^{3} + 3 x^{2} - 4 x - 12

= (x + 1) (x^{3} + 3 x^{2} - 4 x - 12)

Factor

x^{3} + 3 x^{2} - 4 x - 12 : (x + 3) (x + 2) (x - 2)

= (x + 1) (x + 3) (x + 2) (x - 2)

\frac{1}{3} - \frac{3}{4 π}

\frac{3}{2} - \frac{2}{1}

- 5 \times (- 9)

\frac{( x ^{3} - 5 x ^{2} + 7 x - 12 )}{( x - 4 )}

\frac{4 - i}{3 - i}

What is factor x^4+4x^3-x^2-16x-12 ?
The solution to factor x^4+4x^3-x^2-16x-12 is (x+1)(x+3)(x+2)(x-2)