What are the solutions to the equation m^2+2=0 ?

The solutions to the equation m^2+2=0 are m=sqrt(2)i,m=-sqrt(2)i

Find the zeros of m^2+2=0

The zeros of m^2+2=0 are m=sqrt(2)i,m=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 2 = 0

m = 2 i, m = - 2 i

Solution steps

m^{2} + 2 = 0

Move

2

to the right side

m^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 2, m = - - 2

- 2 = 2 i

- - 2 = - 2 i

m = 2 i, m = - 2 i

125 - 8 u^{3}

x^{2} - 2 x - 4 y^{2} - 4 y

2 (2 x^{2} - 3 x) > - 9

- 5 y \leq 15

(x - 6)^{\frac{7}{2}} - 36 (x - 6)^{\frac{3}{2}}

What are the solutions to the equation m^2+2=0 ?
The solutions to the equation m^2+2=0 are m=sqrt(2)i,m=-sqrt(2)i
Find the zeros of m^2+2=0
The zeros of m^2+2=0 are m=sqrt(2)i,m=-sqrt(2)i