What are the solutions to the equation x^2-11x+68=5x+5 ?

The solutions to the equation x^2-11x+68=5x+5 are x=9,x=7

Find the zeros of x^2-11x+68=5x+5

The zeros of x^2-11x+68=5x+5 are x=9,x=7

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x^{2} - 11 x + 68 = 5 x + 5

x = 9, x = 7

Solution steps

x^{2} - 11 x + 68 = 5 x + 5

Move

5

to the left side

x^{2} - 11 x + 63 = 5 x

Move

5 x

to the left side

x^{2} - 16 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 63 = 2

x_{1, 2} = \frac{- ( - 16 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2}{2 \cdot 1} : 9

x = \frac{- ( - 16 ) - 2}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 9, x = 7

x^{2} - x \leq 0

3 (s + 2) - s = 38

x^{2} = \frac{3}{4} x - \frac{1}{8}

(2 x + 3)^{2} = 25

- 4 x - 19 > 33

What are the solutions to the equation x^2-11x+68=5x+5 ?
The solutions to the equation x^2-11x+68=5x+5 are x=9,x=7
Find the zeros of x^2-11x+68=5x+5
The zeros of x^2-11x+68=5x+5 are x=9,x=7