What are the solutions to the equation y^2+6y+8=0 ?

The solutions to the equation y^2+6y+8=0 are y=-2,y=-4

Find the zeros of y^2+6y+8=0

The zeros of y^2+6y+8=0 are y=-2,y=-4

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y^{2} + 6 y + 8 = 0

y = - 2, y = - 4

Solution steps

y^{2} + 6 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

y_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 2}{2 \cdot 1}, y_{2} = \frac{- 6 - 2}{2 \cdot 1}

y = \frac{- 6 + 2}{2 \cdot 1} : - 2

y = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = - 2, y = - 4

- 3 x \geq 6

- \frac{1}{2} \cdot 6

\frac{2 x - 1}{3 x - 2} \leq 0

\frac{\frac{x + h}{x + h + 1} - \frac{x}{x + 1}}{h}

49 x^{2} - 14 x + 2 = 0

What are the solutions to the equation y^2+6y+8=0 ?
The solutions to the equation y^2+6y+8=0 are y=-2,y=-4
Find the zeros of y^2+6y+8=0
The zeros of y^2+6y+8=0 are y=-2,y=-4