What are the solutions to the equation 49x^2-14x+2=0 ?

The solutions to the equation 49x^2-14x+2=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7

Find the zeros of 49x^2-14x+2=0

The zeros of 49x^2-14x+2=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

49 x^{2} - 14 x + 2 = 0

x = \frac{1}{7} + i \frac{1}{7}, x = \frac{1}{7} - i \frac{1}{7}

Solution steps

49 x^{2} - 14 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 49 \cdot 2}{2 \cdot 49}

Simplify

(- 14)^{2} - 4 \cdot 49 \cdot 2 : 14 i

x_{1, 2} = \frac{- ( - 14 ) \pm 14 i}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14 i}{2 \cdot 49}, x_{2} = \frac{- ( - 14 ) - 14 i}{2 \cdot 49}

x = \frac{- ( - 14 ) + 14 i}{2 \cdot 49} : \frac{1}{7} + i \frac{1}{7}

x = \frac{- ( - 14 ) - 14 i}{2 \cdot 49} : \frac{1}{7} - i \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{1}{7}, x = \frac{1}{7} - i \frac{1}{7}

2 x (3 - 4 x) - \frac{x - 2}{5} = \frac{1}{2} (x + 3 - \frac{x - 1}{2})

x^{2} (7 - 6 x) < 1

\frac{1}{5}

3 x + 8 \leq 15

2 (x - 5)^{2} = 0

What are the solutions to the equation 49x^2-14x+2=0 ?
The solutions to the equation 49x^2-14x+2=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7
Find the zeros of 49x^2-14x+2=0
The zeros of 49x^2-14x+2=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7