What are the solutions to the equation 2(x-5)^2=0 ?

The solutions to the equation 2(x-5)^2=0 are x=5

Find the zeros of 2(x-5)^2=0

The zeros of 2(x-5)^2=0 are x=5

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2 (x - 5)^{2} = 0

x = 5

Solution steps

2 (x - 5)^{2} = 0

Divide both sides by

2

(x - 5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 5 = 0 : x = 5

The solution to the quadratic equation is:

x = 5

- 2 x + \frac{1}{3} = \frac{2}{3}

9 n^{2} + 6 n + 1 = 0

\frac{e ^{t}}{e ^{2 t}}

e^{i \cdot \frac{π}{2}}

2 x^{2} - 11 x = 40

What are the solutions to the equation 2(x-5)^2=0 ?
The solutions to the equation 2(x-5)^2=0 are x=5
Find the zeros of 2(x-5)^2=0
The zeros of 2(x-5)^2=0 are x=5