What are the solutions to the equation 9x^2+24x=-16 ?

The solutions to the equation 9x^2+24x=-16 are x=-4/3

Find the zeros of 9x^2+24x=-16

The zeros of 9x^2+24x=-16 are x=-4/3

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9 x^{2} + 24 x = - 16

x = - \frac{4}{3}

Solution steps

9 x^{2} + 24 x = - 16

Move

16

to the left side

9 x^{2} + 24 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 16 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 9}

x = \frac{- 24}{2 \cdot 9}

\frac{- 24}{2 \cdot 9} = - \frac{4}{3}

x = - \frac{4}{3}

The solution to the quadratic equation is:

x = - \frac{4}{3}

3 x^{2} - 122 x + 1195 = 0

17 + 0.03 x \geq 9 + 0.07 x

\frac{2 x - 1}{9} = 3

- 3 x + 2 \leq - 7

3 (x - 2)^{2} (4 x + 1)^{4} + (x - 2)^{3} (4 x + 1)^{3}

What are the solutions to the equation 9x^2+24x=-16 ?
The solutions to the equation 9x^2+24x=-16 are x=-4/3
Find the zeros of 9x^2+24x=-16
The zeros of 9x^2+24x=-16 are x=-4/3