What is 3|x+1|<2|x-10| ?

The solution to 3|x+1|<2|x-10| is -23<x< 17/5

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3|x+1|<2|x-10|

3 ∣ x + 1 ∣ < 2 ∣ x - 10 ∣

- 23 < x < \frac{17}{5}

Solution steps

3 ∣ x + 1 ∣ < 2 ∣ x - 10 ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < 10, x \geq 10

Solve the inequality for each interval

- 23 < x < - 1 or - 1 \leq x < \frac{17}{5} or No Solution

Merge Overlapping Intervals

- 23 < x < \frac{17}{5}

- 4 (x + 8) = - 28

q^{2} + 2 q - 15 = 0

\frac{π}{3} + \frac{π}{4}

\frac{3}{20} - \frac{9}{16}

8 x^{2} - 14