What are the solutions to the equation z^2+z+4=0 ?

The solutions to the equation z^2+z+4=0 are z=-1/2+i(sqrt(15))/2 ,z=-1/2-i(sqrt(15))/2

Find the zeros of z^2+z+4=0

The zeros of z^2+z+4=0 are z=-1/2+i(sqrt(15))/2 ,z=-1/2-i(sqrt(15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} + z + 4 = 0

z = - \frac{1}{2} + i \frac{15}{2}, z = - \frac{1}{2} - i \frac{15}{2}

Solution steps

z^{2} + z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 4 : 15 i

z_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 15 i}{2 \cdot 1}, z_{2} = \frac{- 1 - 15 i}{2 \cdot 1}

z = \frac{- 1 + 15 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{15}{2}

z = \frac{- 1 - 15 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

z = - \frac{1}{2} + i \frac{15}{2}, z = - \frac{1}{2} - i \frac{15}{2}

0.5 n + 0.4 = 4.4

5 x - x^{2} = 2 x

4 + 5 p - p^{2} \geq 0

2.7 \cdot 1 0^{- 4} \cdot m \leq 1.62

x^{2} + 12 x + 35 > 0

What are the solutions to the equation z^2+z+4=0 ?
The solutions to the equation z^2+z+4=0 are z=-1/2+i(sqrt(15))/2 ,z=-1/2-i(sqrt(15))/2
Find the zeros of z^2+z+4=0
The zeros of z^2+z+4=0 are z=-1/2+i(sqrt(15))/2 ,z=-1/2-i(sqrt(15))/2