What are the solutions to the equation 5x^2+2x-2=0 ?

The solutions to the equation 5x^2+2x-2=0 are x=(-1+sqrt(11))/5 ,x=-(1+sqrt(11))/5

Find the zeros of 5x^2+2x-2=0

The zeros of 5x^2+2x-2=0 are x=(-1+sqrt(11))/5 ,x=-(1+sqrt(11))/5

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5 x^{2} + 2 x - 2 = 0

x = \frac{- 1 + 11}{5}, x = - \frac{1 + 11}{5}

Solution steps

5 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- 2) = 211

x_{1, 2} = \frac{- 2 \pm 2 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 2 11}{2 \cdot 5}, x_{2} = \frac{- 2 - 2 11}{2 \cdot 5}

x = \frac{- 2 + 2 11}{2 \cdot 5} : \frac{- 1 + 11}{5}

x = \frac{- 2 - 2 11}{2 \cdot 5} : - \frac{1 + 11}{5}

The solutions to the quadratic equation are:

x = \frac{- 1 + 11}{5}, x = - \frac{1 + 11}{5}

12 1^{\frac{1}{2}}

7 x^{2} + 10 = 18

R (45) = - 30 x^{2} + 2700 x + 30000

(3 + 5)^{2}

2 (4 x + 1) < 3 (2 x - 3)

What are the solutions to the equation 5x^2+2x-2=0 ?
The solutions to the equation 5x^2+2x-2=0 are x=(-1+sqrt(11))/5 ,x=-(1+sqrt(11))/5
Find the zeros of 5x^2+2x-2=0
The zeros of 5x^2+2x-2=0 are x=(-1+sqrt(11))/5 ,x=-(1+sqrt(11))/5