What are the solutions to the equation x^2-12x+30=23 ?

The solutions to the equation x^2-12x+30=23 are x=6+sqrt(29),x=6-sqrt(29)

Find the zeros of x^2-12x+30=23

The zeros of x^2-12x+30=23 are x=6+sqrt(29),x=6-sqrt(29)

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x^{2} - 12 x + 30 = 23

x = 6 + 29, x = 6 - 29

Solution steps

x^{2} - 12 x + 30 = 23

Move

23

to the left side

x^{2} - 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 7 = 229

x_{1, 2} = \frac{- ( - 12 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 29}{2 \cdot 1} : 6 + 29

x = \frac{- ( - 12 ) - 2 29}{2 \cdot 1} : 6 - 29

The solutions to the quadratic equation are:

x = 6 + 29, x = 6 - 29

3 x - 5 > 7 x + 12

\frac{x ^{4} y ^{5}}{x ^{3} y ^{2}}

\frac{\frac{2}{x} - \frac{4}{y}}{\frac{- 5}{y} + \frac{3}{x}}

\frac{25 k - 15}{25 k + 40}

∣ x - 7 ∣ \leq 5

What are the solutions to the equation x^2-12x+30=23 ?
The solutions to the equation x^2-12x+30=23 are x=6+sqrt(29),x=6-sqrt(29)
Find the zeros of x^2-12x+30=23
The zeros of x^2-12x+30=23 are x=6+sqrt(29),x=6-sqrt(29)