What is (2/x-4/y}{\frac{-5)/y+3/x} ?

The solution to (2/x-4/y}{\frac{-5)/y+3/x} is (2y-4x)/(-5x+3y)

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simplify (2/x-4/y}{\frac{-5)/y+3/x}

simplify

\frac{\frac{2}{x} - \frac{4}{y}}{\frac{- 5}{y} + \frac{3}{x}}

\frac{2 y - 4 x}{- 5 x + 3 y}

Solution steps

\frac{\frac{2}{x} - \frac{4}{y}}{\frac{- 5}{y} + \frac{3}{x}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 5}{y} = - \frac{5}{y}

= \frac{\frac{2}{x} - \frac{4}{y}}{- \frac{5}{y} + \frac{3}{x}}

Join

\frac{2}{x} - \frac{4}{y} : \frac{2 y - 4 x}{x y}

= \frac{\frac{2 y - 4 x}{x y}}{- \frac{5}{y} + \frac{3}{x}}

Join

- \frac{5}{y} + \frac{3}{x} : \frac{- 5 x + 3 y}{x y}

= \frac{\frac{2 y - 4 x}{x y}}{\frac{- 5 x + 3 y}{x y}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 y - 4 x ) x y}{x y ( - 5 x + 3 y )}

Cancel

\frac{( 2 y - 4 x ) x y}{x y ( - 5 x + 3 y )} : \frac{2 y - 4 x}{- 5 x + 3 y}

= \frac{2 y - 4 x}{- 5 x + 3 y}

\frac{25 k - 15}{25 k + 40}

∣ x - 7 ∣ \leq 5

4 x^{2} = 20

x^{2} - 1 x - 20 = 0

\frac{2}{3} \cdot 2

What is (2/x-4/y}{\frac{-5)/y+3/x} ?
The solution to (2/x-4/y}{\frac{-5)/y+3/x} is (2y-4x)/(-5x+3y)