What are the solutions to the equation 4x^2=20 ?

The solutions to the equation 4x^2=20 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 4x^2=20

The zeros of 4x^2=20 are x=sqrt(5),x=-sqrt(5)

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4 x^{2} = 20

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

4 x^{2} = 20

Divide both sides by

4

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

x^{2} - 1 x - 20 = 0

\frac{2}{3} \cdot 2

6 x^{2} + 15 x

\frac{- 2 - 12 b}{- 2}

\frac{2 0 ^{0.4} - 1}{\frac{1060}{300} - 1}

What are the solutions to the equation 4x^2=20 ?
The solutions to the equation 4x^2=20 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 4x^2=20
The zeros of 4x^2=20 are x=sqrt(5),x=-sqrt(5)