What is (5k^2-50k+45)/(k^2-18k+81) ?

The solution to (5k^2-50k+45)/(k^2-18k+81) is (5(k-1))/(k-9)

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simplify (5k^2-50k+45)/(k^2-18k+81)

simplify

\frac{5 k ^{2} - 50 k + 45}{k ^{2} - 18 k + 81}

\frac{5 ( k - 1 )}{k - 9}

Solution steps

\frac{5 k ^{2} - 50 k + 45}{k ^{2} - 18 k + 81}

Factor

5 k^{2} - 50 k + 45 : 5 (k - 1) (k - 9)

= \frac{5 ( k - 1 ) ( k - 9 )}{k ^{2} - 18 k + 81}

Factor

k^{2} - 18 k + 81 : (k - 9)^{2}

= \frac{5 ( k - 1 ) ( k - 9 )}{( k - 9 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(k - 9)^{2} = (k - 9) (k - 9)

= \frac{5 ( k - 1 ) ( k - 9 )}{( k - 9 ) ( k - 9 )}

Cancel the common factor:

k - 9

= \frac{5 ( k - 1 )}{k - 9}

- 3 (x + 2) > 18 + 5 x

10 f - 1 > 5 f - 7

\frac{11 !}{( 11 - 3 ) ! 3 !}

3.9 = - 0.5 x^{2} + 0.9 x + 3.8

q^{2} + 40 q + 400 = 36

What is (5k^2-50k+45)/(k^2-18k+81) ?
The solution to (5k^2-50k+45)/(k^2-18k+81) is (5(k-1))/(k-9)